Skip to main content

How to start learning Web-development

Post a Comment

How to calculate adult age in C / C++ language using if-else and switch statment?

Calculating adult age in c languages 

Here we  writing code of c language 

// How to Know that the person is adult and child in c language ?
1.
#include <stdio.h>
#include <conio.h>
int main()
{
    // Here we declared the variable
    int age;
    printf("Enter age of the person :");
    scanf("%d", &age); //Here we entered the age
    // We use if else statement for check that entered age person was child or adult
    if (age > 18)
    {
        printf("This age person is Adult");
    }
    else
    {

        printf("This age person is Child");
    }
    return 0;
}

Output -
Enter the age of the person :12
This age person is Child


2. 
using switch statement 
// making age checker through switch statement

#include <stdio.h>
int main()
{
    int option;
    printf("Enter the option in the following :\n");
    printf("1.Age is greater then 18\n");
    printf("2.Age is lesser then 18\n\n");
    // printf("3.Age is greater then 18\n")

    printf("Entered the option :\n");
    scanf("%d", &option);
    switch (option)
    {
    case 1:
        printf("\nThe person is Adult\n ");
        break;
    case 2:
        printf("\nThe person is Child \n");
        break;

    default:
        printf("Entered option is invalid \n");
        break;
    }
}

Output -
Choose the option in the following :
1.Age is greater then 18
2.Age is lesser then 18

Entered the option :
1

The person is Adult

Making this code in c++ language -

// How to Know that the person is adult and child in c language ?
1 . check the age of the person and result that the person is child or not 
#include <iostream>
using namespace std;
// #include <conio.h>
int main()
{
    // Here we declared the variable
    int age;
    cout << "Enter age of the person :";
    cin >> age; //Here we entered the age
    // We use if else statement for check that entered age person was child or adult
    if (age > 18)
    {
        cout << "This age person is Adult";
    }
    else
    {

        cout << "This age person is Child";
    }
    return 0;
}


output -
Enter the age of the person :12
This age person is Child

2. using switch statement in c++ code -
// Switch statement
#include <iostream>
using namespace std;
int main()
{
    int option;

    cout << "This are the option you have choose : " << endl;
    cout << "1. Age is greater then 18" << endl;
    cout << "2. Age is lesser then 18" << endl;

    cout << "Enter the option :" << endl;
    cin >> option;

    switch (option)
    {
    case 1:
        cout << "The person is Adult" << endl;

        break;
    case 2:
        cout << "The person is child" << endl;

        break;

    default:
        cout << "ENTER VALUE IS INVALID SO REFRESH";
    }
}

output -
choose the option in the following :
1.Age is greater then 18
2.Age is lesser then 18

Entered the option :
1

The person is Adult

c and c++ language is basic and if you learn this language it is very beneficial for you and then anybody can learn any type of language because you know get the basic knowledge about the coding and their IDE's so beginner have to learn c language at least and at the starting of learning they don't required any powerful laptop or pc there work must dine in simple computer or pc 
So i think these program are very helpful to you and in our channel you will get this types for programming tutorial so stay tuned with it and also share our blog with your friends

Comments

Post a Comment

Popular posts from this blog

Funcation in c++ programming example in detail

Friend Funcation- 1. Adding to complex number in friend function #include<iostream> using namespace std; class container { float a,b; public: void get() { cout<<endl<<"Enter value for A="; cin>>a; cout<<endl<<"Enter value for B="; cin>>b; } void disp() { cout<<endl<<a; cout<<endl<<b; } friend container addition(container,container); }; container addition(container X,container y) { container Z; Z.a=X.a+y.a; Z.b=X.b+y.b; return Z; } int main() { container P,Q,R; P.get(); P.disp(); Q.get(); Q.disp(); R=addition(P,Q); R.disp(); return 0; } Output - Enter value for A=12 Enter value for B=12 12 12 Enter value for A=1 Enter value for B=1 1 1 13 13 2.  If class one is friend function of two it not means that two is friend functio...
1 comment
Read more

C++ programming tutorial 2

Control statement in C++ PROGRAMMING - 1. if-else statement :    there are types below of if else statement so they are -     1. if-statement      In this if statement a condition was entered if the condition was match or say what we write in condition on it was true then program was run if it was false then the program in if statement was not run . Syntax - if(Condition){ //code you want to run } PROGRAM - // if-else statement  #include <iostream> using   namespace  std; int   main () {      int   a  ;      cout << "If the entered integer in equal to the condition they it run " << endl ;      cin >>   a ;      if ( a <= 6 )     {          cout << "Program was running" ...
Post a Comment
Read more

C++ programming tutorial 5

 Call by value or reference - There are two type in function call by value or call by reference in it we pass the value in call by value we pass value and in call by reference we pass the reference of the value . Call by value in C++ Programming language  :- In call by value we pass the variable or say argument and then it used by function which we made so see the code given below  Syntax - #include <iostream > using namespace std; // making function  void fun_name(int a, int b) { ... } int main() { //calling function  fun_name(int n,int n1); return 0; } Code -  // function call by value in C++ programming #include <iostream> using namespace std; // call by value in function declaration void container(int a, int b); int main() {   int x,y;   cout<<"Enter the value of x :"<<endl;   cin>>x;   cout<<"Enter the value of y :"<<endl;   cin>>y;   // here we passing the value as argume...
Post a Comment
Read more